For this question, we can use the identity (abc) 2 = a 2 b 2 c 2 2ab abc 2ca (abc) 2 = 250 2(ab bc ca) (abc) 2 = 250 2(3) (abc) 2 = 250 6 (abc) 2 = 256 abc = square root of 256 abc = 16 There you go Hope it helps! Transcript Misc 13 Using properties of determinants, prove that 3a ab ac ba 3b bc ca cb 3c = 3 ( a b c) (ab bc ac) Taking LH S 3a ab ac ba 3b bc ca cb 3c Applying C1 C1 C2 C3 = 3a ab ac ab ac ba 3b bc 3b bc ca cb 3c cb 3c = ab ac 3b bc cb 3c Taking (a b c) common from C1 = ( ) 1 abIn algebra, a quadratic equation (from the Latin quadratus for "square") is any equation that can be rearranged in standard form as = where x represents an unknown, and a, b, and c represent known numbers, where a ≠ 0If a = 0, then the equation is linear, not quadratic, as there is no term The numbers a, b, and c are the coefficients of the equation and may be distinguished by calling
If You Are Given A B C Ab Ac 0 Then How Will You Show That A B C Quora